7 Multivariate Calculus

7.1 Partial derivatives

Practice Problems

Problem 7.1.1: Find the partial derivative with respect to each variable in the problem below:

z=x^2+y^2

Answer:

\frac{\partial z}{\partial x}=2x, \frac{\partial z}{\partial y}=2y

Problem 7.1.2: Find the partial derivative with respect to each variable in the problem below:

z=x^2-5xy-3y^2

Answer:

\frac{\partial z}{\partial x}=2x-5y, \frac{\partial z}{\partial y}=-5x-6y

Problem 7.1.3: Find the partial derivative with respect to each variable in the problem below:

f(x,y)=\frac{x^2y}{y-1}

Answer:

\frac{\partial f}{\partial x}=\frac{2xy}{y-1}, \frac{\partial f}{\partial y}=\frac{-x^2}{(y-1)^2}

Problem 7.1.4: Find the partial derivative with respect to each variable in the problem below:

f(x,y)=(x^2-2xy)^5

Answer:

\frac{\partial f}{\partial x}=5(x^2-2xy)^4(2x-2y), \frac{\partial f}{\partial y}=-10x(x^2-2xy)^4

Problem 7.1.5: Find the partial derivative with respect to each variable in the problem below:

f(x,y,z)=x^2-2y^2+z^2-2xy+3xz-2yz+10xyz-5

Answer:

\frac{\partial f}{\partial x}=2x-2y+3z+10yz, \frac{\partial f}{\partial y}=-4y-2x-2z+10xz, \frac{\partial f}{\partial z}=2z+3x-2y+10xy

Problem 7.1.6: Find the partial derivative with respect to each variable in the problem below:

f(x,y,z)=x^2y-xyz^2+3xz^3-4xy^2+2xz^5

Answer:

\frac{\partial f}{\partial x}=2xy-yz^2+3z^2-4y^2+2z^5, \frac{\partial f}{\partial y}=x^2+xz^2-8xy, \frac{\partial f}{\partial z}=-2xyz+9xz^2+10xz^4

Problem 7.1.7: Find the partial derivative with respect to each variable in the problem below:

f(x,y,z)=(x^2yz-xz^3-xy^2z^2)^8

Answer:

\frac{\partial f}{\partial x}=8(x^2yz-xz^3-xy^2z^2)^7(2xyz-z^3-y^2z^2), \frac{\partial f}{\partial y}=8(x^2yz-xz^3-xy^2z^2)^7(x^2z-2xyz^2), \frac{\partial f}{\partial z}=8(x^2yz-xz^3-xy^2z^2)^7(x^2y-3xz^2-2xy^2z)

Problem 7.1.8: The production function for an economy is given below. Find the equation for the marginal productivity of labor and the marginal productivity of capital (MPL and MPK).

Q=30L^{.8}K^{.2}

Answers:

MP_{L}=\frac{\partial Q}{\partial L}=24\left(\frac{K}{L}\right)^{.2}, MP_{K}=\frac{\partial Q}{\partial K}=6\left(\frac{L}{K}\right)^{.8}

Problem 7.1.9: An individual has the choice to consume different quantities of three goods. The utility function is given below. Find the marginal utility equations for each good.

U(x_1,x_2,x_3)=(5x_1+1)^3(2x_2+4)^2(5x_3+4)^5

Answers:

MU_{1}=\frac{\partial U}{\partial x_{1}}=15(5x_{1}+1)^2(2x_2+4)^2(5x_3+4)^5,MU_{2}=\frac{\partial U}{\partial x_{2}}=4(5x_1+1)^3(2x_2+4)(5x_3+4)^5, MU_{3}=\frac{\partial U}{\partial x_{3}}=25(5x_1+1)^3(2x_2+4)^2(5x_3+4)^4

External Resources

Khan Academy: Partial Derivatives, Introduction

Khan Academy: Graphical Understanding of Partial Derivatives

Khan Academy: Gradients

7.2 Comparative statics

Practice Problems

No practice problems for this section. (Just be able to understand the derivation in the case study from class.)

External Resources

No external resources for this section.

License

Icon for the Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License

Student Companion for Mathematical Economics Copyright © by J. Zachary Klingensmith is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License, except where otherwise noted.

Share This Book