"

Section 4.2 Independence and Dimension

Definition: An indexed set of vectors {v1,,vp} in Rn is said to be linearly independent if the vector equation x1v1++xpvp=0 in Rn has only trivial solution. {v1,,vp} in Rn is said to be linearly dependent if there are c1,,cp not all zero such that c1v1,,cpvp=0. c1v1++cpvp=0 is called the linear dependence relation among v1,,vp.

 

Example 1: Determine if the set {v1,v2,v3} is linearly independent. If possible, find a linear dependence relation among v1,v2,v3. v1=[123], v2=[419], and v3=[246].

 

 

Exercise 1: Determine if the set {v1,v2,v3} is linearly independent. If possible, find a linear dependence relation among v1,v2,v3. v1=[223], v2=[614], and v3=[446].

 

Note: 1. Given a matrix A=[v1,,vp] with p columns, the matrix equation Ax=0 can be written as x1v1++xpvp=0. Then each linear dependence relation among the columns of A corresponds to a nontrivial solution of Ax=0. Hence the columns of matrix A are linearly independent if and only if the equation Ax=0 has only the trivial solution.

 

2. A set with only one vector is linearly independent if and only if it is not a zero vector. The zero vector is linearly dependent.

 

3. A set with two vectors is linearly independent if and only if they are not multiple of each other.

 

Example 2: Show that the column set of A is a linearly independent set. A=[201110121].

 

 

Exercise 2: Show that the column set of A is a linearly independent set. A=[121012120].

 

Theorem: If S={v1,,vp} is an linear independent vectors in Rn, then every vector in Span{v1,,vp} has a unique representation as a linear combination of vis.

 

Note: Geometrically, any two vectors in Rn with n>1 that are not multiple of each other span a plane( they are not co-linear). Any three vectors form a linearly independent set if they are not co-planar.

 

Theorem: If a set contains more vectors than there are entries in each vector, then the set is linearly dependent. That is, any set S={v1,,vp} in Rn is linearly dependent if p>n.

 

Theorem: If S={v1,,vp} in Rn contains the zero vector then it is linearly dependent.

 

Example 3: Use inspection to decide if the vector set is linear independent. State the reasoning.

(a) [211], [422].

(b) [211], [345], [000].

(c) [211], [345], [267], [021].

 

 

Exercise 3: Use inspection to decide if the vector set is linear independent. State the reasoning.

(a) [21], [42], [43].

(b) [2101], [3215], [0000], [2113].

(c) [211], [369], [246].

 

Theorem: The following are equivalent for an n×n matrix A:

1. A is invertible.

2. The column set of A is linearly independent.

3. The column space of A is Rn.

4. The row set of A is linearly independent.

5. The row space of A span the set of all 1×n rows.

 

Example 4: Find the value of h such that the columns of A=[13212h556] is linearly dependent.

 

 

Exercise 4: Find the value of h such that the columns of A=[23h122516] is linearly dependent.

 

Definition: A basis for a subspace H of Rn is a linearly independent set in H that spans H.

 

Fact: The columns of an invertible n×n matrix form a basis of Rn because they are linearly independent and span Rn.

 

Definition: The columns of n×n identity matrix e1=[1000],e2=[0100],,en=[0001]  form a basis of Rn. The set {en,,en} is called standard basis of Rn.

 

Theorem: The pivot columns of a matrix A form a basis for the column space of A.

 

 

Definition: The dimension of a nonzero subspace H, denoted by dim H, is the number of vectors in any basis for H. The dimension of the zero subspace {0} is defined to be zero.

 

The Basis Theorem: If H is a p-dimensional subspace of Rn, then any linearly independent set of exactly p elements in H is automatically a basis for H. Also, any set of p elements of H that spans H is automatically a basis for H.

 

 

Example 5: Find a basis and calculate the dimension of the following
subspaces of Rn:

 

U={[aa+bacb]|a,b,c in R},

V={[abcd]|a+bc+2d=0 in R}.

 

 

Exercise 5: Find a basis and calculate the dimension of the following
subspaces of Rn:

 

U={[aa+ba2cc]|a,b,c in R},

V={[abcd]|a2b+c+d=0 in R}.

 

GroupWork 1: Mark each statement True or False. Justify each answer.

a. If B is an echelon form of a matrix A, then the pivot columns of B form a basis for ColA.

 

b. Row operations do not affect linear dependence relations among the
columns of a matrix.

 

c. The columns of a matrix A are linearly independent if the equation Ax=0 has trivial solution only.

 

d. The columns of any 4×5 matrix are linearly dependent.

 

e. If u and v are linearly independent and if w is in Span{u,v} then {u,v,w} is linearly dependent.

 

f. If three vectors in R3 lie on the same plane, then they are linearly dependent.

 

g. If a set contains fewer vectors than there are entries in the vectors, then
they are linearly independent.

 

h. If a set in Rn is linearly dependent, then it contains more than n vectors.

 

GroupWork 2: Describe the possible echelon form of the matrix.

(a) A is a 2×2 matrix with linearly independent columns.

 

(b) A is a 4×2 matrix such that the first column is the multiple of the second column.

 

GroupWork 3: In each case show that the statement is true, or give an example showing that it is false.

a. If {u,v} is independent, then {u,v,u+v} is independent.

 

b. If {u,v,w} is independent, then {u,v} is independent.

 

c. If {u,v} is dependent, then {u,v,w} is dependent for any w.

 

GroupWork 5: How many pivot columns must be a 6×4 matrix have if its columns are linearly independent.

GroupWork5: How many pivot columns must be a 4×6 matrix have if its columns span R4? Why?

License

Icon for the Creative Commons Attribution 4.0 International License

Matrices Copyright © 2019 by Kuei-Nuan Lin is licensed under a Creative Commons Attribution 4.0 International License, except where otherwise noted.