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Section 6.7 Surface Integral

6.7 Surface Integral

We have integration over a straight line, over a curve, over an flat region( xy-plane), hence it is natural to talk about the integration over a surface. The application is finding the total heat or mass of a piece of thin surface. The idea is the same, we use Riemann sum.

 

Definition: 

The surface integral of a scalar-valued function of f(x,y,z) over a piecewise smooth surface S having a vector equation r(u,v) is:

Sf(x,y,z)dS=limm,ni=1nj=1mf(Pij)Sij

=limm,ni=1nj=1mf(Pij)|ru×rv|uv

=Df(r(u,v))|ru×rv|dudv.

 

 

Example 1: Find S(xy+z)dS where S has a vector equation r(u,v)=<2uv,2u+v,2u+v> where 0u1 and 0v2.

 

 

 

 

Exercise 1: Find S(x+yz)dS where S has a vector equation r(u,v)=<1+u+v,u2v,u+v> where 0u2 and 0v1.

 

 

 

Example 2: Find SydS where S has a vector equation r(u,v)=<v,ucos(v),usin(v)> where 1u2 and 0vπ.

 

 

 

 

Exercise 2: Find SxdS where S has a vector equation r(u,v)=<vsin(u),vcos(u),u> where 0uπ2 and 0v1.

 

 

 

 

For a surface z=g(x,y), we can define a parametric vector function using r(x,y)=<x,y,g(x,y)>, hence we have |rx×ry|=1+gx2+gy2

Sf(x,y,z)dS=Df(x,y,g(x,y))1+gx2+gy2dA.

 

Example 3: Find SxdS where S is the part of the plane x+2y+z=6 lies in the first octant.

 

 

 

 

Exercise 3: Find SydS where S is the part of the plane 2x+3y+z=12 lies in the first octant.

 

 

 

Example 4: Find SxdS where S is the surface y=x2+4z where 0x1 and 0z1.

 

 

 

 

Exercise 4: Find SzdS where S is the surface x=y+2z2 where 0y1 and 0z1.

 

 

 

Example 5: Find S(xyz)dS where S is the part of half cylinder y2+z2=4 with y0 and lies between x=1 and x=1.

 

 

 

 

 

Exercise 5: Find S(x+yz)dS where S is the part of half cylinder x2+z2=4 with x0 and lies between y=0 and y=1.

 

 

 

 

Example 6: Find S(xz)dS where S is the boundary enclosed by the cylinder y2+z2=4 and the planes x=0 and x=1.

 

 

 

Group work:

1. Find S(yz)dS where S is the boundary enclosed by the cylinder x2+y2=4 and the planes z=0 and z=2.

 

2. Find S(y)dS where S is the triangular region bounded by three vertices: (1,0,0), (0,2,0) and (0,0,3).

 

3. Find Sx2dS where S has a vector equation r(u,v)=<u2v,u+v+3,u++2v> where 0u1 and 0v1.

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