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Section 4.5 Cylindrical Integral

4.5 Cylindrical Integral

Recall the Cylindrical Coordinates system is denote a point in a 3-dimensional space via (r,θ,z) where (r,θ) is the polar coordinates of the point project onto the xy-plane. Hence we have relationships,

x2+y2=r2, x=rcos(θ), y=rsin(θ),z=z.

Triple integrals can often be more readily evaluated by using cylindrical coordinates instead of rectangular coordinates. Some common equations

of surfaces in rectangular coordinates along with corresponding equations in cylindrical coordinates are 

Circular cylinder:  x2+y2=r2;

Circular cone:  z2=x2+y2;

Sphere: x2+y2+z2=c2;

Paraboloid:  z=x2+y2.

Definition: Triple Integrals

Consider the cylindrical box (expressed in cylindrical coordinates)

B={(r,θ,z)|arb,αθβ,czd}.

If the function f(r,θ,z) is continuous on B and if (rijk,θijk,zijk) is any sample point in the cylindrical Bijk=[ri1,ri]×[θj1,θj]×[zk1,zk], then we can define the triple integral in cylindrical coordinates as the limit of a triple Riemann sum, provided the following limit exists

liml,m,nli=1mj=1nk=1f(rijk,θijk,zijk)rijkrθz

 if the limit exists.

Theorem: Fubini’s Theorem in Cylindrical Coordinates

Suppose that g(x,y,z) is continuous on a rectangular box B, which when described in cylindrical coordinates looks like B={(r,θ,z)|arb,αθβ,czd}. Then g(x,y,z)=g(rcos(θ),rsin(θ),z)=f(r,θ,z)

and

Bg(x,y,z)dV=dcβαbaf(r,θ,z)rdrdθdz.

The iterated integral may be replaced equivalently by any one of the other five iterated integrals obtained by integrating with respect to the three variables in other orders. 

 

 

Example 1: Evaluating the triple integral B(zrcos(θ))rdrdθdz where B={(r,θ,z)|0r2,π2θπ,0z3}. 

 

 

 

 

Exercise 1: Evaluating the triple integral B(zsin(θ))rdrdθdz where B={(r,θ,z)|0r1,0θπ,0z2}. 

 

 

 

Remark (Theorem): As before, we can do the integration over a general box, not just a cylinder one. Let B={(r,θ,z)|g1(θ)rg2(θ),αθβ,u1(r,θ)zu2(r,θ)} and g(x,y,z)=g(rcos(θ),rsin(θ),z)=f(r,θ,z) be a continuous function over B, then 

Bg(x,y,z)dV=Bf(r,θ,z)rdzdrdθ

=βαg2(θ)g1(θ)u2(r,θ)u1(r,θ)f(r,θ,z)rdzdrdθ

 

Example 2: Let E be the region bounded above by the cone z=2x2+y2 and below by the paraboloid z=x2+y2 . Set up a triple integral in cylindrical coordinates to find the volume of the region.

 

 

 

 

Exercise 2: Let E be the region bounded below by the cone z=2x2+y2 and above by the paraboloid z=3x2y2 . Set up a triple integral in cylindrical coordinates to find the volume of the region.

 

 

 

Example 3: Sketch the solid whose volume is given by the integral and evaluate the integral π2π220r20rdzdrdθ.

 

 

 

 

Exercise 3: Sketch the solid whose volume is given by the integral and evaluate the integral π20100rrdzdrdθ.

 

 

 

Example 4: Sketch the solid. Evaluating the triple integral ExdV where E lies between x2+y2=1, x2+y2=4 above the xy-plane below z=x+2. 

 

 

 

 

Exercise 4: Sketch the solid. Evaluating the triple integral EydV where E lies between x2+y2=2, x2+y2=3 above the xy-plane below z=y. 

 

 

 

Example 5: Sketch the solid and find its volume. The solid is bounded left by xz-plane, right by x2+y2+z2=4, and outside the cylinder x2+z2=1. 

 

 

 

 

Exercise 5: Sketch the solid and find its volume. The solid is bounded below by xy-plane, above by x2+y2+z2=9, and outside the cylinder x2+y2=4. 

 

 

 

Example 6: Sketch the solid and find the volume of the solid lies between the paraboloid x=24y2z2 and the cone x=2y2+z2.

 

 

 

 

Exercise 6: Sketch the solid and find the volume of the solid lies between the paraboloid y=x2+z2 and the cone y=43x2+z2. 

 

 

 

Example 7: Sketch the solid and find its volume. The solid is inside the sphere x2+y2+z2=2, and the paraboloid z=x2+y2. 

 

 

 

Example 8: Change the integration into cylindrical coordinates

224y24y22x2+y2xzdzdxdy

 

 

 

 

Group work:

1. Sketch the solid and find its volume. The solid is inside the sphere x2+y2+z2=4 and the cone y=x2+z2. 

 

2. Change the integration into cylindrical coordinates

4416x2016x2y20x2+y2dzdydx

 

3. Sketch the solid and find its volume. The solid lies inside both

the sphere x2+y2+z2=4 and the cylinder z2+y2=1.

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Multivariable Calculus Copyright © by Kuei-Nuan Lin. All Rights Reserved.