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Section 5.2 Line Integral

5.2 Line Integral

A line integral gives us the ability to integrate multivariable functions and vector fields over arbitrary curves in a plane or in space. There are two types of line integrals: scalar line integrals and vector line integrals. Scalar line integrals are integrals of a scalar function over a curve in a plane or in space. Vector line integrals are integrals of a vector field over a curve in a plane or in space. Let’s look at scalar line integrals first. 

Definition 

Let f be a function with a domain that includes the smooth curve C that is parameterized by r(t)=<x(t),y(t),z(t)>, atb. The scalar line integral of f along C is 

Cf(x,y,z)ds=limni=1nf(Pi)si

if this limit exists. 

If C is a planar curve, then C can be represented by the parametric equations x=x(t),y=y(t), and atb. If C is smooth and f(x,y) is a function of two variables, then the scalar line integral of f along C is defined similarly.

 

 

Theorem: Evaluating a Scalar Line Integral 

Let f be a continuous function with a domain that includes the smooth curve C with parameterization r(t), atb. Then

Cf(x,y,z)ds=abf(r(t))||r(t)||dt.

Theorem: Scalar Line Integral Calculation 

Let f be a continuous function with a domain that includes the smooth curve C with parameterization r(t)=<x(t),y(t),z(t)>, atb. Then

Cf(x,y,z)ds=abf(r(t))(x(t))2+(y(t))2+(z(t))2dt.

Similarly, 

Cf(x,y)ds=abf(r(t))(x(t))2+(y(t))2dt

if C is a planar curve and f is a function of two variables. 

 

Example 1: Evaluate Cyds where C is the curve r(t)=<t2,2t> with 0t2.

 

 

 

 

Exercise 1: Evaluate Cxds where C is the curve r(t)=<3t,t2> with 0t1. 

 

 

 

Example 2: Evaluate Ceyds where C is the line segment from (1,2) to (3,4).

 

 

 

 

Exercise 2: Evaluate Cexds where C is the line segment from (0,1) to (1,2). 

 

 

 

Example 3: Evaluate Cx2+y2zds where C is the part of the helix r(t)=<cos(3t),sin(3t),t>, 0tπ.

 

 

 

 

Exercise 3: Evaluate Cx2+z2+yds where C is the part of the helix r(t)=<cos(2t),t,sin(2t)>, 0tπ2.

 

 

 

Example 4: A wire has a shape that can be modeled with the parameterization r(t)=<cos(t),sin(t),t>, 0t4π. Find the length of the wire.

 

 

 

 

Exercise 4: A wire has a shape that can be modeled with the parameterization r(t)=<sin(t),2t,cos(t)>, 0tπ. Find the length of the wire.

 

 

 

Definition: line integral with respect to arc length

Let C be the curve r(t)=<x(t),y(t),z(t)> then we can define the line integral with resopect to each component of r(t). 

Cf(x,y,z)dx=abf(r(t))x(t)dt

Cf(x,y,z)dy=abf(r(t))y(t)dt

Cf(x,y,z)dz=abf(r(t))z(t)dt.

 

Example 5: Evaluate Cxy+cos(x)dx where C is the arc of x=y2 from (0,0) to (π2,π). 

 

 

 

 

Exercise 5: Evaluate Cx2y+sin(x)dy where C is the arc of y=x2 from (0,0) to (π,π2). 

 

 

 

Definition: We define the integral of F along C as the sum of the integrals of f along each of the smooth pieces of C:

Cf(x,y,z)ds=C1f(x,y,z)ds+C2f(x,y,z)ds++Cnf(x,y,z)ds.

 

Example 6: Evaluate Cx2dx+y2dy where C is the arc of circle x2+y2=9 from (0,3) to (3,0) followed by the line segment from (3,0) to (4,5). 

 

 

 

 

Exercise 6: Evaluate Cydx+xdy where C is the arc of circle x2+y2=1 from (1,0) to (0,1) followed by the line segment from (0,1) to (1,2). 

 

 

 

Example 7: Evaluate Cz2dx+x2dy+y2dz where C is the line segments from (1,0,0) to (1,0,2) and from (1,0,2) to (2,3,4).

 

 

 

Group work:

1. Evaluate Cx2+yzds where C is the curve r(t)=<2t,5t,t>, 0t4.

 

2. Evaluate Cxyds where C is the first half of the circle x2+y2=9 and is traverse in the clockwise direction.

 

3. Evaluate Cy2dx+xdy where C is the arc of x=4y2 from (4,0) to (0,2). 

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Multivariable Calculus Copyright © by Kuei-Nuan Lin. All Rights Reserved.