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Section 6.4 Divergence 

6.4 Divergence 

This section, we learn the divergence of a vector field. The motivation for this is flux of a vector field along a curve or a surface. First, we introduce the flux of a vector field along a curve. 

 

Definition: 

The flux of F across C is line integral

CFN(t)ds

where N(t) is the unit normal vector of the curve.

 

Theorem:Calculating Flux across a Curve 

Let F=<P,Q> be a vector field over R2 and let C be a smooth curve with parameterization r(t)=<x(t),y(t)>, atb. Let n(t)=<y(t),x(t)> . The flux of F across C is 

CF(r(t))n(t)dt=abP(r(t))y(t)dtQ(r(t))x(t)dt=CPdyQdx

 

Example 1: Calculate the flux of F=<2x,2y> across a unit circle oriented counterclockwise.

 

 

 

 

Exercise 1: Calculate the flux of F=<y,x> across a unit circle oriented counterclockwise.

 

 

 

Computing the integration over a curve may not be easy. Hence we want an alternative way for the computation. We introduce the divergence

of a vector field. 

 

Definition:

If F=<P,Q,R> or F=<P,Q> is a vector field in R3 or R2 and Px,Qy and Rz all exist, then the divergence of F is defined

by  divF=Px+Qy+Rz for R3

or 

divF=Px+Qy for R2.

 

Example 2: Find the divergence of F(x,y,z)=xyezi+yzexk.

 

 

 

 

Exercise 2: Find the divergence of F(x,y,z)=xeyj+zeyk.

 

 

 

Example 3: Find the divergence of F(x,y,z)=<exsin(y),eysin(z),ezsin(x)>.

 

 

 

 

Exercise 3: Find the divergence of F(x,y,z)=<eycos(z),excos(y),ezcos(x)>.

 

 

 

Theorem:

If F=<P,Q,R> is a vector field on R3, and P,Q and R have continuous second order paritial derivatives then

div(curl(F))=0.

 

Example 4: Is there a vector filed such that curl(F(x,y,z))=<xsin(y),cos(y),zxy>? Explain.

 

 

 

 

Exercise 4: Is there a vector filed such that curl(F(x,y,z))=<eycos(z),excos(y),ezcos(x)>? Explain.

 

 

 

Theorem: Calculating Flux across a Curve using Green’s Theorem 

Let F=<P,Q> be a vector field over R2, The flux of F across C that enclose a region D is

CF(r(t))n(t)dt=DdivFdA

 

Example 5: Calculate the flux of F=<x2+cos(y),tan(x)+3y> along a curve C from (0,0) to (1,0) to (1,1) to (0,1) and back to (0,0) with the positive orientation. 

 

 

 

 

Exercise 5: Calculate the flux of F=<ex+sin1(y),ey+sec(x)> along a curve C from (1,1) to (2,1) to (2,2) to (1,2) and back to (1,1) with the positive orientation. 

 

 

 

Example 6: Calculate the flux of F=<x2+y2,y2x2> along a curve C from (1,0) to (1,1) to (0,0) and back to (1,0).

 

 

 

 

Exercise 6: Calculate the flux of F=<x3y2,x2y2> along a curve C from (0,0) to (1,0) to (1,1) and back to (0,0).

 

 

 

If F(x,y,z) is the velocity of a fluid (or gas), then divF(x,y,z) represents the net rate of change (with respect to time) of the mass of fluid (or gas) flowing from the point (x,y,z) per unit volume. In other words, divF(x,y,z) measures the tendency of the fluid to diverge from the point (x,y,z). If divF=0, then F is said to be incompressible.

 

 

Group work:

1. Find the divergence of F at a given point P.

a. F=<xy2z4,2x2y+z,y3z2> and P=(1,1,1).

b. F=exsin(y)iexcos(y)j and P=(0,0,2). 

c. F=<exy,exz,eyz> and P=(3,2,0). 

 

2. Calculate the flux of F=<x3y3,y3+x3> along an ellipse C:x2+9y2=9 with positive orientation.

 

3. Calculate the work done by F=<x3y3,y3+x3> by moving an object along an ellipse C:x2+9y2=9 with positive orientation.

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Multivariable Calculus Copyright © by Kuei-Nuan Lin. All Rights Reserved.