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Section 2.2 Wronskian of a differential equation

Objective:

1. The Theorem of super position and IVP.

2. Definition of Wronskian of a differential equation

Recall that if y1 and y2 are solutions to the equation y+p(t)y+q(t)y=0 then the linear combination y=c1y1+c2y2 is also a solution, for all constants c1 and c2. If we are given initial conditions, y(a)=b and y(a)=b, then we can use the initial condition to solve for c1 and c2 and obtain y. 

Computation:

 

 

In order to solve for c1 and c2 and find the y, we need to have the denominator to be not zero. Hence we must have y1(a)y2(a)y1(a)y2(a) is not zero, i.e., 

[y1(a)y2(a)y1(a)y2(a)]0.

 

Definition: W=[y1(t)y2(t)y1(t)y2(t)] is called the Wronskian Determinate  of y1 and y2. 

 

 

Theorem: Suppose y1 and y2 are solutions of the ODE, y+p(t)y+q(t)y=0 with initial conditions y(a)=b,y(a)=b. Then it is always possible to find c1 and c2 such that y=c1y1+c2y2 satisfies the IVP if and only if the Wronskian W=y1y2y1y2 is not zero at t=a. 

 

Example 1: Find the Wronskian of y1=e2t, y2=e3t.

 

 

 

Exercise 1: Find the Wronskian of y1=ety2=e4t. 

 

 

 

Example 2: Find the Wronskian of y1=e2tcos(5t), y2=e2tsin(5t).

 

 

 

Exercise 2: Find the Wronskian of y1=etsin(2t)y2=etcos(2t). 

 

 

 

Example 3: If the Wronskian of f and g is 2e2t and if f(t)=et find g(t).

 

 

 

Exercise 3: If the Wronskian of f and g is 5e2t and if f(t)=e3t find g(t).

 

 

 

Group Work

1. If the Wronskian of f and g is tcos(t)+sin(t), and if u=f3g and v=f+g, find the Wronskian of u and v.

 

2. If the Wronskian of f and g is 2e3t and if f(t)=e2t find g(t).

 

3. If the Wronskian of f and g is etcos(t)+sin(t), and if u=2fg and v=f+2g, find the Wronskian of u and v.

 

4. Find the Wronskian of y1=e4tsin(3t), y2=e4tcos(3t). 

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Differential Equations Copyright © by Kuei-Nuan Lin. All Rights Reserved.