"

Section 4.4 Rank of a Matrix

Definition:  A is a m × n matrix. The column space, Col A, of A is subspace spanned by columns of A. The row space, Row A, of A is the subspace of Rspanned by rows of A.

 

Fact: If A is a reduced-echelon matrix, then the nonzero rows of basis of RowA. The pivot columns of A are a basis of ColA.

 

Definition: The rank of a matrix A, denoted by rankA, is the dimension of the column space of A.


Fact:


1. dim(ColA) = dim(RowA) = rankA.


2. rankA = rankAT

 

The Rank Theorem: If a Matrix A has n columns, then rankA + dim NulA = n

 

Example 1: If the subspace of all solutions of Ax=0
has a basis consisting of three vectors and if A is a 5 x 8 matrix, what is the rank of A?

 

Exercise 1: What is the rank of a 4 x 7 matrix whose null space is two-dimensional?

 

Example 2: Suppose a 4 x 6 matrix A has 4 pivot columns.

Is ColA=R4?

Is NulA=R2?

Explain your answer.

 

 

Exercise 2: Suppose a 4 x 7 matrix A has 3 pivot columns.
Is ColA=R3?

What is the dimension of NulA?

Explain your answer.

 

The Invertible Matrix Theorem:
Let A be an n×n matrix.
Then the following statements are each equivalent to the statement that A is an
invertible matrix.

(a) The columns of A form a
basis of Rn

(b) ColA=Rn

(c) dimColA=n

(d) rankA=n

(e) NulA{0}

(f) dimNulA=0

 

 

 

Theorem: The following are equivalent for an m x n matrix A:

1. rankA=n.

2. The rows of A span Rn.

3. The columns of A are linearly independent in Rm.

4. The n x n matrix ATA is invertible

5. CA=In for some n x m matrix C.

6. If Ax=0,x in Rn, then x=0

 

 

Theorem: The following are equivalent for an m×n matrix A:

1. rankA=m

2. The columns of A span Rm.

3. The rows of A are linearly independent in Rn

4. The m×m matrix AAT is invertible.

5. AC=Im for some n×m matrix C.

6. Ax=b is consistent for every b in Rm.

 

 

Example 3: If A is an m×n matrix and rankA=m,
show that mn.

 

Exercise 3: If A is an m×n matrix and columns of A are linearly independent, show NulA={0}.

 

Group Work Example 1: True or False. Justify each answer:

a. Each line in Rn is a one-dimensional subspace of Rn

 

b. The dimension of ColA is the number of pivot columns of A.

 

c. The dimensions of ColA and NulA add up to the number of columns of A

 

d. If a set of p vectors spans a p-dimensional subspace H of Rn, then these vectors form a basis for H.

 

e. The columns of an invertible n×n matrix form a basis for Rn.

 

f. The dimension of Nul A is the number of variables in the equation Ax=0. The dimension of the column space of A is rankA

 

h. If H is a p-dimensional subspace of Rn, then a linearly independent set of p vectors in H is a basis for H.

 

Group Work 2: Suppose F is a 5×5 matrix whose column space is not equal to R5.
What can you say about Nul F ?

 

Group Work 3: Construct a nonzero 3×4 matrix A such that dimNulA=2 and dimColA=2

a. Can a 3×4 matrix have independent columns? Independent rows? Explain

b. If A is 4×3 and rankA=2, can A have independent columns? Independent rows? Explain

c. Can a non-square matrix have its rows independent and its columns independent? Explain

d. Can the null space of a 3×6 matrix have dimension 2? Explain

 

Group Work 5: Let A be an n×p matrix whose column space is p-dimensional. Explain why the columns of A must be linearly independent

 

Group Work 6: Construct a 4×3 matrix with rank 1

License

Icon for the Creative Commons Attribution 4.0 International License

Matrices Copyright © by Kuei-Nuan Lin is licensed under a Creative Commons Attribution 4.0 International License, except where otherwise noted.